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The magician’s problem

A coin, an audience, and a probability that seems to settle—until you magnify a ripple that never disappears.

A magician hands over a written prediction. The audience stands up. Everyone guesses heads or tails, a coin is tossed, and the people who guessed incorrectly sit down. Repeat. The crowd dwindles, one person remains, and the prediction describes that person.

Wes Iseli performed this routine on Penn & Teller: Fool Us. Watch the audience shrink—and pay attention to what happens when only two people remain.

The original performance, shared on Wes Iseli’s own YouTube channel.

Watch on YouTube ↗

Let chance finish the game

In the performance, the final two people are told to choose different sides. The next toss must leave exactly one standing.

Now remove that instruction. Let everyone make a fresh, independent, fair guess in every round—even the last two. Each person has a half chance of staying. Sometimes the game reaches one person; sometimes the last few people all sit down together.

How does the chance of ever reaching exactly one person depend on the size of the audience?

Try a small version. Each dot is a person, and each click runs one round. This is one simulated performance, not an estimate of the overall probability.

An audience of 64

Round 0 · 64 standing
An audience of 64

Filled dots are standing. Outlined dots have sat down.

Everyone is standing. Will this game reach exactly one?

With just two people, independent play reaches one survivor with probability 2/3. Telling them to choose opposite sides raises that chance to 1. That small change matters.

A very convincing flat line

As the audience grows, the probability seems to settle near 72.13%. The early wiggles shrink so quickly that an ordinary graph appears to have answered the question.

The graph below uses calculated finite-audience probabilities, rather than simulated frequencies. Press Magnify the ripple to look more closely at the almost flat part.

It looks settled

Calculated probabilities
Exact chance of ever reaching one survivor, from 2 to about 4.2 million people. It appears to flatten near 72.13 percent.66%68%70%72%2161281.0k8.2k65.5k524.3k4.2mChance of one survivorAudience size (log scale)

Each horizontal step multiplies the audience size. The dashed line marks the average level, about 72.134752%.

A ripple that remains

From 2¹⁴ to 2²⁰ people
Magnified limiting pattern over six doublings. Its difference from the average repeats between about minus 7.13 and plus 7.13 per million.-8-40482¹⁴2¹⁶2¹⁸2²⁰Difference per millionAudience size

The vertical scale shows the difference from the average, in parts per million. This is the limiting pattern; the finite-audience probabilities approach it.

Chance: 72.1352103%. Difference from the average: +4.58 in a million.

The late ripple has a peak-to-peak height of only about 0.001426 percentage points. Its highest and lowest probabilities differ by roughly 14 in a million.

The early oscillations damp dramatically. But the remaining ripple does not keep shrinking to zero. It repeats at that tiny scale, however far out we go.

Why doubling brings the wiggle back

While the crowd is large, each round removes roughly half of it. Start with twice as many people and, after one extra round, you are roughly back where you started.

So doubling the audience brings the probability back to almost the same place in its cycle. Moving between one power of two and the next takes us through the whole wiggle.

The last few people are where randomness matters most. At that point, “roughly half” can mean two survivors, one survivor, or none. Rounds happen in whole steps, and the game remembers where the starting audience sat between successive powers of two.

In the magnified graph, move along the ripple, then jump 20 more doublings into the distance. The audience is now over a million times larger. The same pattern is still there. Jump again.

Two roads toward infinity

A genuine limiting probability would be the same however we let the audience grow.

Take one route through powers of two: 256, 512, 1,024, and so on. Take another with audiences about 1.414… times as large—the square root of two times those sizes, rounded down. Keep doubling on both routes.

Two routes, two different destinations

Two sequences of growing audiences approach different probabilities. Powers of two approach 72.1352103 percent; powers of two times the square root of two, rounded down, approach 72.1342938 percent.-8-4048816243240Difference per millionNumber of doublings
Powers of twoPowers of two × √2, rounded down

Both audiences keep growing. The solid and dashed curves approach different levels.

Both routes become enormous, yet they approach different probabilities:

  • Powers of two: approximately 72.1352103%.
  • Powers of two × √2, rounded down: approximately 72.1342938%.

The gap is tiny, but it stays. That is enough to rule out a single limit.

Almost settled

On an ordinary scale, this probability looks constant. On a finer scale, it keeps moving through the same cycle. More people stretch the oscillation across larger audience sizes; they do not erase its final, very small height.

That is the surprise hiding behind the coin: a probability can look settled to several decimal places and still never converge.

For the exact formulas, proofs, and connections with random leader election, read the full mathematical write-up.