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Trigonometric derivatives

Connect sine and cosine to their slopes, then apply the differentiation rules.

The idea

Sine rises, flattens, falls, and repeats. Its tangent slope follows the same repeating pattern as cosine. The paired graphs below connect a function’s height with its rate of change.

Rules

Sine and cosine

\[\frac{d}{dx}\sin x=\cos x,\qquad \frac{d}{dx}\cos x=-\sin x.\]

Both rules hold for every real input, with the angle in radians.

Derivations (optional)

Use the angle-addition identities and the earlier limits

\[\lim_{h\to0}\frac{\sin h}{h}=1,\qquad \lim_{h\to0}\frac{\cos h-1}{h}=0.\]

The second follows from \(\frac{\cos h-1}{h}=-h\frac{1-\cos h}{h^2}\) and the previously established cosine limit. Then

\[\begin{aligned} \frac{d}{dx}\sin x &=\lim_{h\to0}\frac{\sin(x+h)-\sin x}{h}\\ &=\lim_{h\to0}\left[\sin x\frac{\cos h-1}{h}+\cos x\frac{\sin h}{h}\right]\\ &=\sin x\cdot0+\cos x\cdot1=\cos x. \end{aligned}\]

Similarly,

\[\begin{aligned} \frac{d}{dx}\cos x &=\lim_{h\to0}\frac{\cos(x+h)-\cos x}{h}\\ &=\lim_{h\to0}\left[\cos x\frac{\cos h-1}{h}-\sin x\frac{\sin h}{h}\right]\\ &=\cos x\cdot0-\sin x\cdot1=-\sin x. \end{aligned}\]
Compare the sine curve with its derivative Drag either point horizontally. The upper point follows sine with an amber tangent. The lower point records that tangent slope on the cosine curve. 1−11−1
\(f(x)=\sin x\)\(f^{\prime}(x)=\cos x\)
\(0\)\(\pi\)\(2\pi\)\(x\) \(0\)\(\pi\)\(2\pi\)\(x\)
\(x=\) 0.79 rad\(f(x)=\) 0.71\(f^{\prime}(x)=\) 0.71

Drag either point. The amber tangent's slope in the upper graph is the height of the point in the lower graph.

At \(x=\pi/2\), sine is at a crest and its slope is \(0\). At \(x=\pi\), it crosses zero while falling, and its slope is \(-1\). The derivative tracks change, not height.

The other four functions

Their derivatives follow from the quotient rule.

Rules

Tangent, cotangent, secant, and cosecant

\[\frac{d}{dx}\tan x=\sec^2 x,\qquad \frac{d}{dx}\cot x=-\csc^2 x.\] \[\frac{d}{dx}\sec x=\sec x\tan x,\qquad \frac{d}{dx}\csc x=-\csc x\cot x.\]

Use these only where the original functions are defined: \(\cos x\ne0\) for tangent and secant; \(\sin x\ne0\) for cotangent and cosecant.

For example, the quotient rule explains the tangent rule:

\[\frac{d}{dx}\tan x=\frac{\cos x\cos x-\sin x(-\sin x)}{\cos^2x}=\frac{1}{\cos^2x}=\sec^2x.\]

Worked examples

Example 1

An angle that also changes

For \(y=\sin(x^2)\), the inner angle is \(x^2\). Use the chain rule:

\[\frac{dy}{dx}=\cos(x^2)\cdot2x.\]

Differentiate sine at the current angle, then multiply by the rate at which that angle changes.

Example 2

A quotient and an identity

For \(q(x)=\frac{\cos x}{1+\sin x}\), where \(1+\sin x\ne0\),

\[\begin{aligned} q^{\prime}(x)&=\frac{(-\sin x)(1+\sin x)-\cos x\cos x}{(1+\sin x)^2}\\ &=\frac{-\sin x-(\sin^2x+\cos^2x)}{(1+\sin x)^2}\\ &=-\frac{1}{1+\sin x}. \end{aligned}\]

The identity \(\sin^2x+\cos^2x=1\) makes the simplification possible. The original domain restriction remains.

Example 3

Position and velocity in periodic motion

An object has position \(s(t)=2\cos(3t)\) metres, with time in seconds and the angle \(3t\) in radians. Its instantaneous velocity is

\[s^{\prime}(t)=-2\sin(3t)\cdot3=-6\sin(3t)\,\mathrm{m/s}.\]

At \(t=\pi/6\) seconds, the object has position \(0\) and velocity \(-6\,\mathrm{m/s}\). It is passing through the origin in the negative direction, rather than stopping there.

The coefficient \(2\) is the amplitude: maximum displacement from the centre. The coefficient \(3\) is the angular frequency, describing how quickly the angle changes in radians per second.

Quiz

Calculus for Engineers and Scientists

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