Problem
Cutting a cube
A solid \(3\times3\times3\) cube consists of 27 unit cubes joined together, like an idealized Rubik’s Cube. What is the minimum number of straight planar cuts needed to separate all 27 cubes?
You may rearrange and stack the pieces between cuts, but each unit cube must remain intact.
Hint
Which unit cube is hardest to free?
Solution
Look at the middle cube. It has six neighbours, one sharing each of its six faces. To free it, all six shared faces must be cut.
A straight planar cut can run along at most one of these faces, since no two lie in the same plane. Rearranging or stacking the pieces does not change this: the middle cube still needs a separate cut along each face. Thus, at least six cuts are necessary.
Six cuts also suffice: make two parallel cuts in each of the three directions, along the unit-cube boundaries. This separates the original cube into all 27 unit cubes.
The minimum is therefore \(\boxed{6}\).